3.284 \(\int \frac{(c \sin (a+b x))^{5/2}}{(d \cos (a+b x))^{9/2}} \, dx\)

Optimal. Leaf size=37 \[ \frac{2 (c \sin (a+b x))^{7/2}}{7 b c d (d \cos (a+b x))^{7/2}} \]

[Out]

(2*(c*Sin[a + b*x])^(7/2))/(7*b*c*d*(d*Cos[a + b*x])^(7/2))

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Rubi [A]  time = 0.059941, antiderivative size = 37, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.04, Rules used = {2563} \[ \frac{2 (c \sin (a+b x))^{7/2}}{7 b c d (d \cos (a+b x))^{7/2}} \]

Antiderivative was successfully verified.

[In]

Int[(c*Sin[a + b*x])^(5/2)/(d*Cos[a + b*x])^(9/2),x]

[Out]

(2*(c*Sin[a + b*x])^(7/2))/(7*b*c*d*(d*Cos[a + b*x])^(7/2))

Rule 2563

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_Symbol] :> Simp[((a*Sin[e +
f*x])^(m + 1)*(b*Cos[e + f*x])^(n + 1))/(a*b*f*(m + 1)), x] /; FreeQ[{a, b, e, f, m, n}, x] && EqQ[m + n + 2,
0] && NeQ[m, -1]

Rubi steps

\begin{align*} \int \frac{(c \sin (a+b x))^{5/2}}{(d \cos (a+b x))^{9/2}} \, dx &=\frac{2 (c \sin (a+b x))^{7/2}}{7 b c d (d \cos (a+b x))^{7/2}}\\ \end{align*}

Mathematica [A]  time = 0.16591, size = 40, normalized size = 1.08 \[ \frac{2 \cot (a+b x) (c \sin (a+b x))^{9/2}}{7 b c^2 (d \cos (a+b x))^{9/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*Sin[a + b*x])^(5/2)/(d*Cos[a + b*x])^(9/2),x]

[Out]

(2*Cot[a + b*x]*(c*Sin[a + b*x])^(9/2))/(7*b*c^2*(d*Cos[a + b*x])^(9/2))

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Maple [A]  time = 0.066, size = 38, normalized size = 1. \begin{align*}{\frac{2\,\cos \left ( bx+a \right ) \sin \left ( bx+a \right ) }{7\,b} \left ( c\sin \left ( bx+a \right ) \right ) ^{{\frac{5}{2}}} \left ( d\cos \left ( bx+a \right ) \right ) ^{-{\frac{9}{2}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*sin(b*x+a))^(5/2)/(d*cos(b*x+a))^(9/2),x)

[Out]

2/7/b*sin(b*x+a)*cos(b*x+a)*(c*sin(b*x+a))^(5/2)/(d*cos(b*x+a))^(9/2)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (c \sin \left (b x + a\right )\right )^{\frac{5}{2}}}{\left (d \cos \left (b x + a\right )\right )^{\frac{9}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(5/2)/(d*cos(b*x+a))^(9/2),x, algorithm="maxima")

[Out]

integrate((c*sin(b*x + a))^(5/2)/(d*cos(b*x + a))^(9/2), x)

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Fricas [A]  time = 3.21275, size = 150, normalized size = 4.05 \begin{align*} -\frac{2 \,{\left (c^{2} \cos \left (b x + a\right )^{2} - c^{2}\right )} \sqrt{d \cos \left (b x + a\right )} \sqrt{c \sin \left (b x + a\right )} \sin \left (b x + a\right )}{7 \, b d^{5} \cos \left (b x + a\right )^{4}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(5/2)/(d*cos(b*x+a))^(9/2),x, algorithm="fricas")

[Out]

-2/7*(c^2*cos(b*x + a)^2 - c^2)*sqrt(d*cos(b*x + a))*sqrt(c*sin(b*x + a))*sin(b*x + a)/(b*d^5*cos(b*x + a)^4)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))**(5/2)/(d*cos(b*x+a))**(9/2),x)

[Out]

Timed out

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Giac [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*sin(b*x+a))^(5/2)/(d*cos(b*x+a))^(9/2),x, algorithm="giac")

[Out]

Timed out